Singapore’s Toh Wei Soong ends Asian Para Games campaign with two silvers, three bronzes
Toh now has 12 medals from four Games campaigns.
Toh Wei Soong at the 2026 Asian Para Games. (Photo: SNPC/Goh Si Wei)
New: You can now listen to articles.
This audio is generated by an AI tool.
Read a summary of this article on FAST.
Get bite-sized news via a new
cards interface. Give it a try.
Click here to return to FAST
Tap here to return to FAST
FAST
SINGAPORE: Swimmer Toh Wei Soong added another medal to his haul on Friday (Oct 23) to end his 2026 Asian Para Games campaign with two silvers and three bronzes.
At the Nagoya City General Gymnasium, the 28-year-old defending champion clocked a time of 29.22s to clinch silver in the men’s 50m freestyle S7.
China’s Zhang Yilong won gold (28.85s), while Uzbekistan’s Sardor Bakhtiyorov took bronze (29.72s).
Toh won the event at the last two Games and set the meet record in 2023 with a time of 28.81s. Zhang, however, had a qualifying time quicker than Toh’s Games mark coming into Friday’s race.
With his latest haul, the Singaporean now has a total of 12 medals from the Games. This is the first Games since his debut in 2014 that Toh has concluded his campaign without a gold medal.
At the previous edition of the Games in Hangzhou, Toh won the 50m butterfly S7, 50m freestyle S7, and the 100m backstroke S7, taking silver in the 400m freestyle S7. He also won two golds and a bronze at the 2018 Games.
Singapore’s athletes have now bagged five silvers and five bronzes at the Games, with one day of competition remaining. Boccia athletes Aloysius Gan and Nurulasyiqah Mohd Taha will aim to end the gold medal drought on Saturday when they compete in the mixed pair BC3 final.
Source: CNA/mt
Sign up for our newsletters
Get the CNA app
Stay updated with notifications for breaking news and our best stories
Get WhatsApp alerts
Join our channel for the top reads for the day on your preferred chat app
Get bite-sized news via a new
cards interface. Give it a try.
Click here to return to FAST
Tap here to return to FAST
FAST
